TRICKY MATH RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

Playing Chess with Aire, as Chess is a two person game! Did you answer this riddle correctly?
YES  NO  

Obtuse Did you answer this riddle correctly?
YES  NO  

The loss is $100. Did you answer this riddle correctly?
YES  NO  

121

Explanation
Tables consist of squares of the number from 4 to 12.
11^2 = 121. Did you answer this riddle correctly?
YES  NO  

Justoneword Did you answer this riddle correctly?
YES  NO  

The number 8. On its side, the number 8 looks like an infinity symbol. Cut in half, the number 8 becomes two zeros. Did you answer this riddle correctly?
YES  NO  

If you said 5000 you're wrong! The answer is 4100, how?

1000 + 40 = 1040
1040 + 1000 + 30 = 2070
2070 + 1000 + 20 = 3090
3090 + 1000 = 4090
4090 + 10 = 4100 Did you answer this riddle correctly?
YES  NO  

Her eye sight Did you answer this riddle correctly?
YES  NO  

Your eyes because you are sleeping! Did you answer this riddle correctly?
YES  NO  

Answer: 87

Explanation:

If you look at the upside down you will see that the series is actually

86, 87, 88, 89, 90, 91

So the answer is 87. Did you answer this riddle correctly?
YES  NO  

Total Money taken = $100($50+$50)

Now,

Bag's Price = $ 97

Remaining Amount = $100 - $97

= $ 3

Returned = $ 1 + $ 1

=$2

In pocket = $1

Total money owed = $100- ( Returned amount)

= $98( Bag's amount and reserved amount)

So, it was a calculation mistake. Did you answer this riddle correctly?
YES  NO  

12 (Twelve) has 6 letters,

6 (Six) has 3

Therefore,

10 (Ten) will be equal to 3 Did you answer this riddle correctly?
YES  NO  

The neighbour borrowed an extra cow, to make the total number of cows 18. Then the oldest son got 1/2 of 18 is 9 cows, the middle son got 1/3 of 18 is 6 cows, and the youngest son got 1/9 of 18 is 2 cows. Since 9+6+2 = 17, the cows could be divided among the three brothers in such a way that the borrowed cow was left over, and could be returned to its owner. Did you answer this riddle correctly?
YES  NO  

Six on one side - six on the other = one side is heavier.

Take the heavier six men, divide them into three and three (random).

Three on one side - three on the other = one side will one heavier.

Divide that three men from the heavier side side, have one on one side - one on the other.

Two results can determine which of the last three men weight is a different weight than each other.

With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.

Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.

You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."

Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
YES  NO  

Pandas

"Eats-shoots-leaves." Pandas "eat", then "shoot" then "leave". Did you answer this riddle correctly?
YES  NO