Find Me In A Palm Tree Riddle
This is a fruit that contains some water
And can provide milk and oil for cooking
If you ever want to see one growing
On a palm tree's where you should be looking
And can provide milk and oil for cooking
If you ever want to see one growing
On a palm tree's where you should be looking
Hint:
Made Of Sugar Riddle
I am sometimes made of sugar
And sometimes of oatmeal
Chocolate chip ones taste so good
You might find that you squeal!
What could I be?
And sometimes of oatmeal
Chocolate chip ones taste so good
You might find that you squeal!
What could I be?
Hint:
On Everyones Face Riddle
We are a pair, We can dart here and there, Though we always stay in one place. We can smile or shed tears, Show our pleasure or fears, And you'll find us on everyone's face.
What are we?
What are we?
Hint:
Dropping Coconuts Riddle
You have two coconuts and you want to find out how high they can be dropped from a 100 story building before they break. But you only have $1.40 and the elevator costs a dime each time you ride it up (it's free for rides down).
How can you drop the coconuts to guarantee you will find the lowest floor they will break at, while starting and ending at floor 1?
How can you drop the coconuts to guarantee you will find the lowest floor they will break at, while starting and ending at floor 1?
Hint: They break when dropped from the same height and they don't weaken from getting dropped.
You could drop it at floor 1 first (because you start at floor 1). Then you would go to the floors: 14, 27, 39, 50, 60, 69, 77, 84, 90, 95, 99, and 100. Whatever floor your first coconut breaks at, go to the floor above the last floor the coconut survived and drop the second coconut from this floor. Then go up by one floor until the second coconut breaks and that is the lowest floor it will break at. Did you answer this riddle correctly?
YES NO
YES NO
Finding The Clue
Hint:
12 Islanders Teeter Totter Riddle
There is an island with 12 islanders. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11.
You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. There are no scales or other weighing device on the island.
How can you find out which islander is the one that has a different weight?
You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. There are no scales or other weighing device on the island.
How can you find out which islander is the one that has a different weight?
Hint:
Six on one side - six on the other = one side is heavier.
Take the heavier six men, divide them into three and three (random).
Three on one side - three on the other = one side will one heavier.
Divide that three men from the heavier side side, have one on one side - one on the other.
Two results can determine which of the last three men weight is a different weight than each other.
With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.
Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.
You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."
Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
YES NO
Take the heavier six men, divide them into three and three (random).
Three on one side - three on the other = one side will one heavier.
Divide that three men from the heavier side side, have one on one side - one on the other.
Two results can determine which of the last three men weight is a different weight than each other.
With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.
Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.
You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."
Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
YES NO
12 Pills Riddle
You have 12 pills and they all got the same weight, except for one, which hasn't got the same weight. You don't know if it is heavier or easier. You have one scale to weight the pills. You now have to find out, which pill is the right one (the one with a different weight), but you can use the scale only three times. How do you know, which one is the right one?You have 12 pills and they all got the same weight, except for one, which hasn't got the same weight. You don't know if it is heavier or easier. You have one scale to weight the pills. You now have to find out, which pill is the right one (the one with a different weight), but you can use the scale only three times. How do you know, which one is the right one?
Hint:
E = easier in "1", H = heavier in "1". 1: Weight 4:4. If they balance go to "2", if they don't balance, go to "3". 2: Balance 1:1 of the pills you didn't weight yet. Then weight one you didn't weight and one you did weight. If they balanced in the first weighing, and balanced in the second weighing, the last pill is the right one. If they balanced in the first weighing and didn't balance in the second, the one you didn't use before is the right pill. If they didn't balance at all, it's the pill you weighed twice. If they didn't balance in the first weighing, but balanced in the second, it is the first pill. 3: Weight EHH : EHH. If they balance, weight one you already weighed, with an unweighed and go to "4". If they don't balance go to "5". 4: If they balance, the one you didn't weight at all is the right pill. If they don't balance, the one you only weighed once is the right one. 5: Give away every pill that was once easier AND once heavier. You should only have EHH left. Weight H:H. If they balance, E is the right one. If the don't balance, the one which was only heavier the whole time, is the right pill. Did you answer this riddle correctly?
YES NO
YES NO
I May Be Simple I May Be Complex Riddle
I may be simple, I may be complex; I may have a name, but no gender or sex; I am often a question, or statements as a setup; I tend to have an answer, 'til you find it I won't let up. What am I?
Hint:
This Lady Is All In Riddle
Black's 100, blue's 10, red's 5. This lady is all in. If to pass this door you strive, Find the total the dame's holdin.'
Hint: There are 3 colors. Blue, red and black.
From these, we must find at the correct answer. What about the poker chips were on the table?
Rivers With No Water Riddle
Hint: I represent an area of land or sea.
What Gets Wetter And Wetter The More It Dries Riddle
Hint: We use it everyday.
What Goes Up And Down Without Moving Riddle
Hint:
Closed Areas Riddle
Hint:
4
Look at how many closed areas there are.
9999 has 4 closed areas (the top of the '9')
8888 has 8 closed areas, the top and bottom parts of the 8 and there are no other digits
1816 has 3 closed areas, (top and bottom of 8 and bottom of 6, and it has 2 other digits ( 3*2=6)
1212 has 0 closed areas,(0*4=0) Did you answer this riddle correctly?
YES NO
Look at how many closed areas there are.
9999 has 4 closed areas (the top of the '9')
8888 has 8 closed areas, the top and bottom parts of the 8 and there are no other digits
1816 has 3 closed areas, (top and bottom of 8 and bottom of 6, and it has 2 other digits ( 3*2=6)
1212 has 0 closed areas,(0*4=0) Did you answer this riddle correctly?
YES NO
Birthday In September Riddle
A man born in March has his birthday in September. Although he was orphaned as a young child he grew up and married his father. How is this possible?
Hint:
He was born in the town of March, about 25 miles north of Cambridge, England. He grew up to be the mayor of his town, and performed the wedding ceremony for the head of his local church. Did you answer this riddle correctly?
YES NO
YES NO
The Shortest Month Riddle
Hint:
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