Come Seek Us Riddle
Come seek us where our voices sound,
We cannot sing above the ground,
And while you're searching ponder this;
We've taken what you'll sorely miss,
An hour long you'll have to look,
And to recover what we took,
But past an hour, the prospect's black,
Too late it's gone, it won't come back.
(egg song) from movie:
Come seek us where our voices sound,
We cannot sing above the ground,
An hour long you'll have to look,
To recover what we took.
We cannot sing above the ground,
And while you're searching ponder this;
We've taken what you'll sorely miss,
An hour long you'll have to look,
And to recover what we took,
But past an hour, the prospect's black,
Too late it's gone, it won't come back.
(egg song) from movie:
Come seek us where our voices sound,
We cannot sing above the ground,
An hour long you'll have to look,
To recover what we took.
Hint:
Singing To The Queen Riddle
Hint:
Singing In Groups Riddle
Hint:
A Ram's Favorite Tune Riddle
Hint:
A Neck Thats Long
This is not a giraffe
But it has a neck thats long
Its something with six strings
And is used to play a song
What is this?
But it has a neck thats long
Its something with six strings
And is used to play a song
What is this?
Hint:
Thick And Slick Riddle
I am thin although sometimes thick. I am slick although sometimes rough. I am used by an artiste whom doesn't draw nor paint. Im a?
Hint:
Spiriting Faultless Pitch
Without a partner, I sit here mutely. My grace and beauty for you to reckon. Bright head above a regal neck, soft curves. And promise of my rich voice do beckon. Im inevitably hollow, the fretful type, but with practice, I could be your soul mate: If you hold me just right, I'll resonate your spiriting faultless pitch, your song to elevate. What could I be?
Hint:
Finding The Clues
Hercule Poirot Detective reviewed the information they had on the case so far.
A lady named 'monica' was found shot and Hercule already had a list of suspects: rooney, torres, dabid, messi, ronaldo
Killer is a fan of Hercule and chalenge him by leaving notes at various places.
# The first was found in a drawing room.
# The second was found in an art room.
# The third was in a bed room.
# the fourth in an ice-cream room.
# The fifth at the desk room
All of the notes read the same thing, 'The clues are where you find the notes.' Still, nothing was found anywhere.
Hercule Poirot pause for a moment and then arrested the killer. Who was the killer?
A lady named 'monica' was found shot and Hercule already had a list of suspects: rooney, torres, dabid, messi, ronaldo
Killer is a fan of Hercule and chalenge him by leaving notes at various places.
# The first was found in a drawing room.
# The second was found in an art room.
# The third was in a bed room.
# the fourth in an ice-cream room.
# The fifth at the desk room
All of the notes read the same thing, 'The clues are where you find the notes.' Still, nothing was found anywhere.
Hercule Poirot pause for a moment and then arrested the killer. Who was the killer?
Hint:
Dabid is the killer
drawing room(D) , art room(a) , bed room (b) , ice-cream room (i) , desk room (d) Did you answer this riddle correctly?
YES NO
drawing room(D) , art room(a) , bed room (b) , ice-cream room (i) , desk room (d) Did you answer this riddle correctly?
YES NO
Playing Chess Riddle
Two people are playing Chess. They play five games. They both win three games. With out any ties, draws, or surrenders, how is this possible?
Hint:
Cutting Your Food Riddle
If you open a kitchen drawer
This is something that you might see
Smaller ones are used to cut your food
And larger ones to carve turkey
What is it?
This is something that you might see
Smaller ones are used to cut your food
And larger ones to carve turkey
What is it?
Hint:
Sock Singing Riddle
Hint:
Matching Socks Riddle
Mismatched Joe is in a pitch dark room selecting socks from his drawer. He has only six socks in his drawer, a mixture of black and white. If he chooses two socks, the chances that he draws out a white pair is 2/3. What are the chances that he draws out a black pair?
Hint: Three pairs of matching socks... maybe not!!!
He has a ZERO chance of drawing out a black pair.
Since there is a 2/3 chance of drawing a white pair, then there MUST be 5 white socks and only 1 black sock. The chances of drawing two whites would thus be: 5/6 x 4/5 = 2/3 . With only 1 black sock, there is no chance of drawing a black pair. Did you answer this riddle correctly?
YES NO
Since there is a 2/3 chance of drawing a white pair, then there MUST be 5 white socks and only 1 black sock. The chances of drawing two whites would thus be: 5/6 x 4/5 = 2/3 . With only 1 black sock, there is no chance of drawing a black pair. Did you answer this riddle correctly?
YES NO
Four Balls In A Bowl
This is a famous paradox probability riddle which has caused a great deal of argument and disbelief from many who cannot accept the correct answer.
Four balls are placed in a bowl. One is Green, one is Black and the other two are Yellow. The bowl is shaken and someone draws two balls from the bowl. He looks at the two balls and announces that at least one of them is Yellow. What are the chances that the other ball he has drawn out is also Yellow?
Four balls are placed in a bowl. One is Green, one is Black and the other two are Yellow. The bowl is shaken and someone draws two balls from the bowl. He looks at the two balls and announces that at least one of them is Yellow. What are the chances that the other ball he has drawn out is also Yellow?
Hint:
1/5
There are six possible pairings of the two balls withdrawn,
Yellow+Yellow
Yellow+Green
Green+Yellow
Yellow+Black
Black+Yellow
Green+Black.
We know the Green + Black combination has not been drawn.
This leaves five possible combinations remaining. Therefore the chances tbowl the Yellow + Yellow pairing has been drawn are 1 in 5.
Many people cannot accept tbowl the solution is not 1 in 3, and of course it would be, if the balls had been drawn out separately and the color of the first ball announced as Yellow before the second had been drawn out. However, as both balls had been drawn together, and then the color of one of the balls announced, then the above solution, 1 in 5, must be the correct one. Did you answer this riddle correctly?
YES NO
There are six possible pairings of the two balls withdrawn,
Yellow+Yellow
Yellow+Green
Green+Yellow
Yellow+Black
Black+Yellow
Green+Black.
We know the Green + Black combination has not been drawn.
This leaves five possible combinations remaining. Therefore the chances tbowl the Yellow + Yellow pairing has been drawn are 1 in 5.
Many people cannot accept tbowl the solution is not 1 in 3, and of course it would be, if the balls had been drawn out separately and the color of the first ball announced as Yellow before the second had been drawn out. However, as both balls had been drawn together, and then the color of one of the balls announced, then the above solution, 1 in 5, must be the correct one. Did you answer this riddle correctly?
YES NO
The Secret Santa Exchange
A group of ten friends decide to exchange gifts as secret Santas. Each person writes his or her name on a piece of paper and puts it in a hat. Then each person randomly draws a name from the hat to determine who has him as his or her secret Santa. The secret Santa then makes a gift for the person whose name he drew.
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
Hint: It's not as difficult as it seems.
It's the number of ways the friends can form a circle divided by the number of ways the names can be drawn out of the hat.
1/10
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
The Cheap Mp3 Player
My MP3 player is cheap 'n' nasty and has now broken: it is stuck on 'Shuffle'. In this mode it starts with whatever track you put it on, but then plays tracks in a random order. The only restriction is it never plays a song that's already been played that day.
I purchased my favourite murder mystery book in audio format, and put the first 6 chapters on my MP3 player. (Each chapter is exactly 1 track.) There's nothing else on my player at the moment. What is the probability that I will hear the 6 chapters in order as I listen today, without having to change tracks at all? (Obviously, I will ensure it plays chapter 1 first.)
The next day I empty the player before putting on the next 6 chapters. This time I also transfer a CD of mine with 11 songs on. I don't mind songs coming in between the chapters of my book, as long as the chapters are in order. What's the probability of that happening now?
I purchased my favourite murder mystery book in audio format, and put the first 6 chapters on my MP3 player. (Each chapter is exactly 1 track.) There's nothing else on my player at the moment. What is the probability that I will hear the 6 chapters in order as I listen today, without having to change tracks at all? (Obviously, I will ensure it plays chapter 1 first.)
The next day I empty the player before putting on the next 6 chapters. This time I also transfer a CD of mine with 11 songs on. I don't mind songs coming in between the chapters of my book, as long as the chapters are in order. What's the probability of that happening now?
Hint:
With only 6 tracks on the player:
The first chapter has been set to play first. The probability of the next 5 chapters playing in order is 1/5! = 1/120.
With the music on the player as well:
Seeing as I don't care about when the music plays, it doesn't change anything. The answer is still 1/120. Did you answer this riddle correctly?
YES NO
The first chapter has been set to play first. The probability of the next 5 chapters playing in order is 1/5! = 1/120.
With the music on the player as well:
Seeing as I don't care about when the music plays, it doesn't change anything. The answer is still 1/120. Did you answer this riddle correctly?
YES NO
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