TO WHAT KIND OF ANIMAL NEEDS TO WEAR A WIG RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

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Riddles and Answers © 2024

The Biggest Cleats Riddle

Hint:
The one with the biggest feet!
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Five Prom Couples Riddle

Hint:
Mark and Susan wore red.
Quintin and Jessica wore blue.
Jim and Amanda wore pink.
Bob and Betty wore green.
James and Jasmin wore yellow.
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Dracula's Dog Riddle

Hint:
A bloodhound
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Cowbell Riddle

Hint:
Because their horns dont work.
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Random Slamming Doors

Hint:
It is in a haunted house
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Stockings Hung Over Me

Hint:
A fireplace
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The Blind Mammals Riddle

Hint:
They are bats!
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Parents, Shepherds And Kings

Hint:
A Nativity Scene
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Three People Holding Gifts Riddle

Hint:
A nativity scene!
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Displayed In December

Hint:
A nativity scene
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A Bath Without Water

Hint:
A sun bath
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Wet Coat Riddle

Hint:
A coat of paint
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Ears On An Engine Riddle

Hint:
Engineers.
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Four Balls In A Bowl

Hint:
1/5

There are six possible pairings of the two balls withdrawn,
Yellow+Yellow
Yellow+Green
Green+Yellow
Yellow+Black
Black+Yellow
Green+Black.

We know the Green + Black combination has not been drawn.

This leaves five possible combinations remaining. Therefore the chances tbowl the Yellow + Yellow pairing has been drawn are 1 in 5.

Many people cannot accept tbowl the solution is not 1 in 3, and of course it would be, if the balls had been drawn out separately and the color of the first ball announced as Yellow before the second had been drawn out. However, as both balls had been drawn together, and then the color of one of the balls announced, then the above solution, 1 in 5, must be the correct one.
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Knights Of The Round Table Riddle

Hint: Does it matter if they are sitting clockwise or counterclockwise? Or where the oldest sits?
The odds are 11:1. (The probability is 1/12.)

Imagine they sat down in age order, with each person randomly picking a seat. The first person is guaranteed to pick a seat that "works". The second oldest can sit to his right or left, since these five can sit either clockwise or counterclockwise. The probability of picking a seat that works is thus 2/4, or 1/2. The third oldest now has three chairs to choose from, one of which continues the progression in the order determined by the second person, for a probability of 1/3. This leaves two seats for the fourth oldest, or a 1/2 chance. The youngest would thus be guaranteed to sit in the right seat, since there is only one seat left. This gives 1 * 1/2 * 1/3 * 1/2 * 1 = 1/12, or 11:1 odds against.
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