IM HARD ALL AROUND BUT SOFT IN THE MIDDLE WHAT AM I RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

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Riddles and Answers © 2024

In The Middle Of Tennis Riddle

Hint:
Annette
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The Middle Of China Riddle

Hint:
The letter 'I'.
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A Hard Key Riddle

Hint:
A donkey.
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As Hard As Stone Riddle

Hint:
Ice
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At The Hardware Store Riddle

Hint:
Prices quoted were for house numbers at 12 cents per number. A number'6' cost me 12 cents.
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3 Doraemon Images

Hint:
Look at the eyes of all the three images. The second one has eyes positioned at different places. This is why the second image is the odd one out.
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Prince Age Riddle

Hint:
Current Future Past

Princess x 2z (x+y)/2
Prince y x z

I then created three equations, since the difference in their age will always be the same.

d = the difference in ages

x y = d
2z x = d
x/2 + y/2 z = d

I then created a matrix and solved it using row reduction.

x y z

1 -1 0 d
-1 0 2 d
.5 .5 -1 d

It reduced to:

x y z

1 0 0 4d
0 1 0 3d
0 0 1 5d/2

This means that you can pick any difference you want (an even one presumably because you want integer ages).

Princess age: 4d
Prince age: 3d

Ages that work

Princess:
4
8
16
24
32
40
48
56
64
72
80

Prince:
3
6
12
18
24
30
36
42
48
54
60
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In The Middle Of The Ocean

Hint:
It will be the same because the boat floats.
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White And Soft

Hint:
Coconut
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Speaking With A Hard Tongue

Hint:
A bell
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In The Middle Of Paris

Hint:
The letter r
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An Island That Has 3 Gods

Hint:
Question 1: (To any of the three gods) If I were to ask you "Is that the random god," would your answer be "ja?" (This questions, no matter the answer, will enable you to tell which god is not random i.e. the god who is either False or True)

Question 2: (To either the True or False god) If I asked you "are you false," would your answer be "ja?"

Question 3: (To the same god you asked the second question) If I asked you "whether the first god I spoke to is random," would your answer be "ja?"
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Middle Ages Riddle

Hint:
Knight-time.
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The Most Important Bee

Hint:
The queen
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Age Of Three Daughters Riddles

Hint:
3, 3, and 8. The only groups of 3 factors of 72 to have non-unique sums are 2 6 6 and 3 3 8 (with a sum of 14). The rest have unique sums:

2 + 2 + 18 = 22
2 + 3 + 12 = 18
2 + 4 + 9 = 15
3 + 4 + 6 = 13

The house number alone would have identified any of these groups. Since more information was required, we know the sum left the answer unknown. The presence of a single oldest child eliminates 2 6 6, leaving 3 3 8 as the only possible answer.
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