Cut Through Evil
I cut through evil like a double edged sword, And chaos flees at my approach. Balance I single-handedly upraise, Through battles fought with heart and mind, Instead of with my gaze.
What am I?
What am I?
Hint:
I Join You In Battle Riddle
I join you in battle, fist clenched tight.
We pound three times with all our might.
If my rival decides he will sign for peace;
I'll crush him, and the fight will cease.
But if he lays his hand down flat;
I'll suffer defeat, that is that.
What am I?
We pound three times with all our might.
If my rival decides he will sign for peace;
I'll crush him, and the fight will cease.
But if he lays his hand down flat;
I'll suffer defeat, that is that.
What am I?
Hint:
A Small Shop Riddle
I am all over Hong Kong. I am a small shop. My name is two numbers. I sell snacks and newspapers. Where could this place be?
Hint:
Combination Value Riddle
The letters A through H can be assigned the following values to make all the equations true. Find the right combination of letter values.
Values: 1, 4, 5, 7, 9, 14, 16, 21
C + F = G
A + C = F
B + G = D
B + E = H
D + F = H
Values: 1, 4, 5, 7, 9, 14, 16, 21
C + F = G
A + C = F
B + G = D
B + E = H
D + F = H
Hint:
Twenty In The Pool
Hint:
50 Quarters Riddle
You have fifty quarters on the table in front of you. You are blindfolded and cannot discern whether a coin is heads up or tails up by feeling it. You are told that x coins are heads up, where 0 < x < 50. You are asked to separate the coins into two piles in such a way that the number of heads up coins in both piles is the same at the end. You may flip any coin over as many times as you want.
How can you do it?
How can you do it?
Hint:
Take x coins, flip all of them and put them in one pile. The rest of the coins form the second pile. Did you answer this riddle correctly?
YES NO
YES NO
Four And Five Riddle
Hint:
The Dinner Party Riddle
You and your wife organize a dinner party. You invite four other husband-wife couples. You and your wife don't necessarily know everyone you invited. Once everyone is at the party, the people who don't know each other yet shake hands with each other. You can assume that everyone knows their own wife/husband, and that no one shakes their own hand.
After this happens, you ask each person, except for yourself, how many people they shook hands with. Everybody tells you a different number.
How many people did your wife shake hands with?
After this happens, you ask each person, except for yourself, how many people they shook hands with. Everybody tells you a different number.
How many people did your wife shake hands with?
Hint:
Your wife shook hands with 4 people
If everybody shook hands with a different number of people, then the most any person shook hands with was 8 people, and in fact, a single person must have shaken hands with exactly 8 people. Figure out exactly who this person did - and didn't - shake hands with. Then go from there. Did you answer this riddle correctly?
YES NO
If everybody shook hands with a different number of people, then the most any person shook hands with was 8 people, and in fact, a single person must have shaken hands with exactly 8 people. Figure out exactly who this person did - and didn't - shake hands with. Then go from there. Did you answer this riddle correctly?
YES NO
Equals Eight Riddle
Hint:
Mirror one of the threes and put it and the other three together to get an eight. Did you answer this riddle correctly?
YES NO
YES NO
Fastest Horse Riddle
The London Racetrack needs to submit its 3 fastest horses to the Kentucky Derby out of 25 horses. However, all of their information was lost and they don't know any of the horse's times. Similarly, they all look identical so they can't remember who's fastest.
They can only race 5 horses at once, so what is the fewest number of races they can conduct to find the 3 fastest horses?
They can only race 5 horses at once, so what is the fewest number of races they can conduct to find the 3 fastest horses?
Hint:
First you divide the 25 horses into 5 groups of 5. You conduct the 5 races and take all of the fastest horses in those races and have a race with them, giving you the fastest horse. Then you take the remaining 24 horses (excluding the fastest) and remove the 4th and 5th horses in the first set of 5 races (since they definitely have 3 horses faster than them), leaving you with 14 horses. Next you can remove all of the horses that were beat in the preliminary race by the horses that got 4th and 5th in the championship race, leaving you with 8 horses. Finally, you can remove the horses that remain that lost to the 3rd place horse in the final race in the preliminary race and the horse that got 3rd in the preliminary to the horse that got 2nd in the championship race, leaving you with 5 horses.
You can then run a final race where the 1st and 2nd place horses are the 2nd and 3rd fastest. Then you know the 3 fastest horses. Did you answer this riddle correctly?
YES NO
You can then run a final race where the 1st and 2nd place horses are the 2nd and 3rd fastest. Then you know the 3 fastest horses. Did you answer this riddle correctly?
YES NO
Five Hundred Riddle
Five hundred begins it, five hundred ends it, Five in the middle is seen; First of all figures, the first of all letters, Take up their stations between. Join all together, and then you will bring Before you the name of an eminent king. Who am I?
Hint:
Dial 666
Hint:
9 Golf Balls
You know that out of your 9 golf balls there is one that is lighter than the others. But, the light ball is to small a difference for the "hand balance!" You're in luck, the course you're at has a scale, but you can only afford to use it 2 times. How do you figure it out?
Hint:
STEP 1: Divide it into sets of three. If you put one set on either side, it'll either equal the same, or you'll see which set is lighter. Either way, you narrow it down to three balls.
STEP 2: put two of the balls on the scale. If they're equal, the last ball is defective, but if not, the scale will tell you which one is lighter. Did you answer this riddle correctly?
YES NO
STEP 2: put two of the balls on the scale. If they're equal, the last ball is defective, but if not, the scale will tell you which one is lighter. Did you answer this riddle correctly?
YES NO
30 Sacks Of Coconuts
An intelligent trader travels from one place to another with 3 sacks having 30 coconuts each. No sack can hold more than 30 coconuts. On the way, he passes 30 check points. At each check point, he has to give one coconut for every sack he is carrying. What is the maximum number of coconuts that he can have with him at the end of his journey?
Hint:
He will have 25 coconuts with him at the end. The trick is to reduce the number of sacks as you pass checkpoints.
The first 10 checkpoints require 3 coconuts each, which empties his first sack. The next 15 checkpoints require 2 coconuts each, which will empty his second stack. Now, he is left with 1 sack and 5 more checkpoints. So, the 5 checkpoints will take 1 coconut each. Therefore, he will be left with 25 coconuts. Did you answer this riddle correctly?
YES NO
The first 10 checkpoints require 3 coconuts each, which empties his first sack. The next 15 checkpoints require 2 coconuts each, which will empty his second stack. Now, he is left with 1 sack and 5 more checkpoints. So, the 5 checkpoints will take 1 coconut each. Therefore, he will be left with 25 coconuts. Did you answer this riddle correctly?
YES NO
The Murder Of Ray Whitcombe
Ray Whitcombe is found dead in his office at his desk. The police have narrowed the suspects down to three people: Mrs. Barbara Whitcombe, Ray's wife; Mr. Jason McCubbins, Ray's business partner; and Mr. Harold Nichols, Ray's best friend. All three visited Mr. Whitcombe the day of his murder, but all three provide the police with stories of explanation as to the reason for their visit. Police found Mr. Whitcombe with his wrist watch still on his right arm, a torn up picture of his wife laying on the floor beside the trash can, and an ink pen in his right hand. On the desk, the police found a name plate, a telephone that was off the hook, and a personal calendar turned to the July 5th page with 7B91011 written on it. After examining this evidence, the police knew their suspect. Who was it?
Hint:
Jason McCubbins, Ray's business partner. The calendar is the clue to solving this murder. The police realized that since Mr. Whitcombe was wearing his watch on his right arm, he must be left handed. But the pen was found in his right hand. Realizing that the number on the calendar was written in a hurry and with his opposite hand, police matched the written number with the months of the year. So the B was an 8, thereby giving us 7-8-9-10-11: July, August, September, October, November. Use the first letter of each month and it spells J-A-S-O-N. Did you answer this riddle correctly?
YES NO
YES NO
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