I Come As A Pair
I come as a pair but Im not jeans
I have several digits but Im not a cellphone
I have an arch but Im not a bridge
I have nails but I dont have a hammer
Im part of the body but Im not a hand
What part of the body am I?
I have several digits but Im not a cellphone
I have an arch but Im not a bridge
I have nails but I dont have a hammer
Im part of the body but Im not a hand
What part of the body am I?
Hint:
White And Brittle
These are a part of your body
Sometimes theyre large, sometimes theyre little
Theyre white and they can be broken
And in some people they are brittle
What could these things be?
Sometimes theyre large, sometimes theyre little
Theyre white and they can be broken
And in some people they are brittle
What could these things be?
Hint:
A Suit In A Deck Of Cards
I'm red but Im not a strawberry
I'm a shape but Im not a square
I'm part of your body but Im not your mouth
I'm a suit in a deck of cards but Im not a spade
I'm used to say I love you but Im not a diamond
I'm a?
I'm a shape but Im not a square
I'm part of your body but Im not your mouth
I'm a suit in a deck of cards but Im not a spade
I'm used to say I love you but Im not a diamond
I'm a?
Hint:
I See London I See France
Hint:
Transforming Nature Riddle
This part of nature gets transformed
But it's not summer becoming fall
It starts as a caterpillar
But emerges with wings colorful
But it's not summer becoming fall
It starts as a caterpillar
But emerges with wings colorful
Hint:
Blown Up Like A Stick Of Dynamite
I get blown up but Im not a stick of dynamite
I sometimes have a string attached but Im not a kite
I sometimes float but Im not a swimmer
Im seen at birthday parties but Im not a candle
What could I be?
I sometimes have a string attached but Im not a kite
I sometimes float but Im not a swimmer
Im seen at birthday parties but Im not a candle
What could I be?
Hint:
Isn't A Mermaid Riddle
What has beautiful hair, a pretty face, two arms, a fishs tail, looks like a mermaid, but isnt a mermaid?
Hint:
7B91011 Riddle
Ray Whitcombe was found dead in his office at his desk. The police have narrowed the suspects down to three people:
Mrs. Barbara Whitcombe, Ray's wife
Mr. Jason McCubbins, Ray's business partner
Mr. Harold Nichols, Ray's best friend
All three visited Mr. Whitcombe the day of his murder, but all three provided the police with stories of explanation as to the reason for their visit.
Police found Mr. Whitcombe with his wrist watch still on his right arm, a torn up picture of his wife laying on the floor beside the trash can, and an ink pen in his right hand. On the desk, the police found a name plate, a telephone that was off the hook, and a personal calendar turned to the July 5th page with 7B91011 written on it. After examining this evidence, the police knew their suspect.
Who was it?
Mrs. Barbara Whitcombe, Ray's wife
Mr. Jason McCubbins, Ray's business partner
Mr. Harold Nichols, Ray's best friend
All three visited Mr. Whitcombe the day of his murder, but all three provided the police with stories of explanation as to the reason for their visit.
Police found Mr. Whitcombe with his wrist watch still on his right arm, a torn up picture of his wife laying on the floor beside the trash can, and an ink pen in his right hand. On the desk, the police found a name plate, a telephone that was off the hook, and a personal calendar turned to the July 5th page with 7B91011 written on it. After examining this evidence, the police knew their suspect.
Who was it?
Hint:
Jason McCubbins, Ray's business partner.
The calendar was the clue to solving this murder. The police realized that since Mr. Whitcombe was wearing his watch on his right arm, he must have been left-handed. Realizing that the number on the calendar was written in a hurry and with his opposite hand, police matched the written number with the months of the year. So the B was an 8, thereby giving us 7-8-9-10-11: July, August, September, October, November. Use the first letter of each month and it spells J-A-S-O-N. Did you answer this riddle correctly?
YES NO
The calendar was the clue to solving this murder. The police realized that since Mr. Whitcombe was wearing his watch on his right arm, he must have been left-handed. Realizing that the number on the calendar was written in a hurry and with his opposite hand, police matched the written number with the months of the year. So the B was an 8, thereby giving us 7-8-9-10-11: July, August, September, October, November. Use the first letter of each month and it spells J-A-S-O-N. Did you answer this riddle correctly?
YES NO
Where Vampires Live
Hint:
Three People At A Bus Stop Riddle
You're driving down the road in your car on a wild and stormy night. The weather is like a hurricane, with heavy rains, high winds, and lightning flashing constantly. While driving, you come across a partially-covered bus stop, and you can see three people waiting for a bus:
1. An old woman who looks as if she is about to die.
2. An old friend who once saved your life.
3.The perfect partner you have been dreaming about (your soulmate).
Knowing that you only have room for one passenger in your car (its a really small car), which one would you choose to offer a ride to? And why?
1. An old woman who looks as if she is about to die.
2. An old friend who once saved your life.
3.The perfect partner you have been dreaming about (your soulmate).
Knowing that you only have room for one passenger in your car (its a really small car), which one would you choose to offer a ride to? And why?
Hint:
I would give the car keys to my old friend, and let him take the old woman to the hospital. Then I would stay behind and wait for the bus with the partner of my dreams. Did you answer this riddle correctly?
YES NO
YES NO
What Has Cities Forests And Water
Hint:
Librarians Bait Riddle
Hint:
12 Islanders Teeter Totter Riddle
There is an island with 12 islanders. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11.
You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. There are no scales or other weighing device on the island.
How can you find out which islander is the one that has a different weight?
You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. There are no scales or other weighing device on the island.
How can you find out which islander is the one that has a different weight?
Hint:
Six on one side - six on the other = one side is heavier.
Take the heavier six men, divide them into three and three (random).
Three on one side - three on the other = one side will one heavier.
Divide that three men from the heavier side side, have one on one side - one on the other.
Two results can determine which of the last three men weight is a different weight than each other.
With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.
Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.
You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."
Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
YES NO
Take the heavier six men, divide them into three and three (random).
Three on one side - three on the other = one side will one heavier.
Divide that three men from the heavier side side, have one on one side - one on the other.
Two results can determine which of the last three men weight is a different weight than each other.
With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.
Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.
You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."
Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
YES NO
Eight Pills Riddle
There are 8 pills. They are all the same size and color. One pill weighs slightly more and is poisonous. You have a balanced scale and you can only use it twice. How can you find the poisonous Pill?
Hint:
Take any six pills and divide them into two groups of three each. Weigh putting the 3 pills on each side. If one side weigh's heavier than another, the heavier side consists of the poisonous pill. From the three pill in heavier side, weigh two pills. If one pill is heavier than another, the heavy one is poisonous pill. If both pill weigh same, the remaining third pill is poisonous. If all the 6 pill weigh the same, weigh the remaining two pill and heavy one is poisonous. Did you answer this riddle correctly?
YES NO
YES NO
What Remains When The Roads Are Gone Riddle
A race car driver has completed 12 1/2 laps of a 50-lap race. What fractional part of the race remains?
Hint:
Let's take a look at the explanation of the riddle.
As per the total laps in the race are 50 and the driver has completed 12 1/2 laps. This means, we have to subtract 12 1/2 from the total 50 laps. This equal to 37 1/2 or 37.5
50 - 12 1/2 = 37 1/2 or 37.5
Now, we need to calculate the fractional part of the race remains. For this, we need to divide the remaining laps by total laps, that is, 37 1/2 divide by 50 or 37.5 divided by 50 which will be equal to 0.74 or 3/4.
37 1/2 / 50 = 0.74 or 3/4
Hence, the right answer to the riddle is 3/4 Did you answer this riddle correctly?
YES NO
As per the total laps in the race are 50 and the driver has completed 12 1/2 laps. This means, we have to subtract 12 1/2 from the total 50 laps. This equal to 37 1/2 or 37.5
50 - 12 1/2 = 37 1/2 or 37.5
Now, we need to calculate the fractional part of the race remains. For this, we need to divide the remaining laps by total laps, that is, 37 1/2 divide by 50 or 37.5 divided by 50 which will be equal to 0.74 or 3/4.
37 1/2 / 50 = 0.74 or 3/4
Hence, the right answer to the riddle is 3/4 Did you answer this riddle correctly?
YES NO
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