YOUR IF THE RED HOUSE IS ON THE RIGHT SIDE AND IF THE BLUE HOUSE IS ON THE LEFT SIDE WHERES THE WHITE HOUSE RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

Heart Did you answer this riddle correctly?
YES  NO  

A bottle of gin. Did you answer this riddle correctly?
YES  NO  

Question 1: (To any of the three gods) If I were to ask you "Is that the random god," would your answer be "ja?" (This questions, no matter the answer, will enable you to tell which god is not random i.e. the god who is either False or True)

Question 2: (To either the True or False god) If I asked you "are you false," would your answer be "ja?"

Question 3: (To the same god you asked the second question) If I asked you "whether the first god I spoke to is random," would your answer be "ja?" Did you answer this riddle correctly?
YES  NO  

A spider. Did you answer this riddle correctly?
YES  NO  

School Bus Did you answer this riddle correctly?
YES  NO  

A bus Did you answer this riddle correctly?
YES  NO  

A doorbell Did you answer this riddle correctly?
YES  NO  

Oranges Did you answer this riddle correctly?
YES  NO  

A potato Did you answer this riddle correctly?
YES  NO  

Lead. Lead is a metallic gray, is very heavy and in order to stay ahead of someone, you need to be in the lead. Did you answer this riddle correctly?
YES  NO  

Teeth. Did you answer this riddle correctly?
YES  NO  

38

Logic :
From 1st the hexagon shape has value 15.
The shape has 15 edges(6 of hexagon,5 of Pentagon and 4 of Square)
From 2nd we get value of one bunch of bananas is 4.
So each banana has value of 1.
From 3rd we get that each clock has value of 3.
Which resembles the time on the clock which is 3.
Hence by using these insights, we get the last required values as
Clock = 2 (2 in the clock)
Bananas = 3 (3 bananas in the bunch)
Hexagon = 11 (Hexagon[6 sides] and pentagon[5 sides], so 6+5=11)
So required value is
2+3+3x11=?
2+3+33=? (Multiply first - Bodmas rule)
5+33=38 and hence the answer is 38. Did you answer this riddle correctly?
YES  NO  

A possible solution is:

Q1: Ask god B, "If I asked you 'Is A Random?', would you say ja?". If B answers ja, either B is Random (and is answering randomly), or B is not Random and the answer indicates that A is indeed Random. Either way, C is not Random. If B answers da, either B is Random (and is answering randomly), or B is not Random and the answer indicates that A is not Random. Either way, you know the identity of a god who is not Random.

Q2: Go to the god who was identified as not being Random by the previous question (either A or C), and ask him: "If I asked you 'Are you False?', would you say ja?". Since he is not Random, an answer of da indicates that he is True and an answer of ja indicates that he is False.

Q3: Ask the same god the question: "If I asked you 'Is B Random?', would you say ja?". If the answer is ja, B is Random; if the answer is da, the god you have not yet spoken to is Random. The remaining god can be identified by elimination. Did you answer this riddle correctly?
YES  NO  

Your right hand Did you answer this riddle correctly?
YES  NO  

7, we asked 'how many candles' not 'how many lit candles' Did you answer this riddle correctly?
YES  NO