The Month Of December Riddle
Hint: The answer is in the riddle
High In The Sky Riddle
I was high in the sky but also firmly on the earth
I brought cooperation for many but confusion for all
I was unmissable by the crowd yet overlooked by the One
I was the world's first true skyscraper and also its last
I am in the Bible - what am I?
I brought cooperation for many but confusion for all
I was unmissable by the crowd yet overlooked by the One
I was the world's first true skyscraper and also its last
I am in the Bible - what am I?
Hint:
Running Windows Riddle
Name a five letter word which has three consonants all the same and two different vowels. Every now and then you see this while running a Windows 95/98 on your PC.
Hint:
Java Light Bulb Riddle
Hint:
One, to generate a "ChangeLightBulb" event to the socket. Did you answer this riddle correctly?
YES NO
YES NO
Selling Windows Riddle
Hint:
Opening Doors Riddle
While driving his car a man slams on the brakes when he sees, in the middle of the street, a diamond studded door, a gold door and a silver door. Which door does he open first?
Hint:
Website Nurse Riddle
Hint:
The Coffin Riddle:
The man who built it doesn't want it, the man who bought doesn't need it, the man who needs it doesn't know it. Body parts remaining: 6
Hint:
Cranberry Sauce And Pumpkin Pie
Thirty days of autumn bliss
I hold the holiday you won't want to miss
The home of cranberry sauce and pumpkin pie
Which month of the year am I?
I hold the holiday you won't want to miss
The home of cranberry sauce and pumpkin pie
Which month of the year am I?
Hint:
Logs Aflame Riddle
This can be found working inside some homes during the winter months
But can you work out its name?
Surrounded by a mantelpiece
It has logs that are aflame
But can you work out its name?
Surrounded by a mantelpiece
It has logs that are aflame
Hint:
Going To High Places
My invention makes it easier for people to get to high places without climbing stairs. What did I invent?
Hint:
Dropping Coconuts Riddle
You have two coconuts and you want to find out how high they can be dropped from a 100 story building before they break. But you only have $1.40 and the elevator costs a dime each time you ride it up (it's free for rides down).
How can you drop the coconuts to guarantee you will find the lowest floor they will break at, while starting and ending at floor 1?
How can you drop the coconuts to guarantee you will find the lowest floor they will break at, while starting and ending at floor 1?
Hint: They break when dropped from the same height and they don't weaken from getting dropped.
You could drop it at floor 1 first (because you start at floor 1). Then you would go to the floors: 14, 27, 39, 50, 60, 69, 77, 84, 90, 95, 99, and 100. Whatever floor your first coconut breaks at, go to the floor above the last floor the coconut survived and drop the second coconut from this floor. Then go up by one floor until the second coconut breaks and that is the lowest floor it will break at. Did you answer this riddle correctly?
YES NO
YES NO
100 Blank Cards Riddle
Someone offers you the following deal:
There is a deck of 100 initially blank cards. The dealer is allowed to write ANY positive integer, one per card, leaving none blank. You are then asked to turn over as many cards as you wish. If the last card you turn over is the highest in the deck, you win; otherwise, you lose.
Winning grants you $50, and losing costs you only the $10 you paid to play.
Would you accept this challenge?
There is a deck of 100 initially blank cards. The dealer is allowed to write ANY positive integer, one per card, leaving none blank. You are then asked to turn over as many cards as you wish. If the last card you turn over is the highest in the deck, you win; otherwise, you lose.
Winning grants you $50, and losing costs you only the $10 you paid to play.
Would you accept this challenge?
Hint: Perhaps thinking in terms of one deck is the wrong approach.
Yes!
A sample strategy:
Divide the deck in half and turn over all lower 50 cards, setting aside the highest number you find. Then turn over the other 50 cards, one by one, until you reach a number that is higher than the card you set aside: this is your chosen "high card."
Now, there is a 50% chance that the highest card is contained in the top 50 cards (it is or it isn't), and a 50% chance that the second-highest card is contained in the lower 50. Combining the probabilities, you have a 25% chance of constructing the above situation (in which you win every time).
This means that you'll lose three out of four games, but for every four games played, you pay $40 while you win one game and $50. Your net profit every four games is $10.
Obviously, you have to have at least $40 to start in order to apply this strategy effectively. Did you answer this riddle correctly?
YES NO
A sample strategy:
Divide the deck in half and turn over all lower 50 cards, setting aside the highest number you find. Then turn over the other 50 cards, one by one, until you reach a number that is higher than the card you set aside: this is your chosen "high card."
Now, there is a 50% chance that the highest card is contained in the top 50 cards (it is or it isn't), and a 50% chance that the second-highest card is contained in the lower 50. Combining the probabilities, you have a 25% chance of constructing the above situation (in which you win every time).
This means that you'll lose three out of four games, but for every four games played, you pay $40 while you win one game and $50. Your net profit every four games is $10.
Obviously, you have to have at least $40 to start in order to apply this strategy effectively. Did you answer this riddle correctly?
YES NO
Shoe Man Whistle
Hint:
The third equation has a term with a pair of whistles. The last line involves a single whistle.
Furthermore, the man in the second and third lines are wearing a whistle, but the man in the last line is not wearing a whistle. Presumably the value of the whistle should be accounted for to get the correct answer.
The pictures can be translated into the following equations:
shoes + shoes + shoes = 30
shoes + (man + whistle) + (man + whistle) = 20
(man + whistle) + 2(whistles) + 2(whistles) = 13
shoes + (man) x (whistle) = ?
From the first equation we can solve for the shoes value:
shoes + shoes + shoes = 30
3(shoes) = 30
shoes = 10
We can then solve the second equation for the (man + whistle) value:
shoes + (man + whistle) + (man + whistle) = 20
10 + 2(man + whistle) = 20
2(man + whistle) = 10
man + whistle = 5
Then we solve the third equation for the whistle:
(man + whistle) + 2(whistles) + 2(whistles) = 13
5 + 4(whistles) = 13
4(whistles) = 8
whistle = 2
We also need to solve for the value of the man:
man + whistle = 5
man + 2 = 5
man = 3
Now we can evaluate the final expression, remembering the order of operations that multiplication should be evaluated before addition:
shoes + (man) x (whistle) = ?
10 + 3 x 2
= 10 + 3 x 2
= 10 + 6
= 16 Did you answer this riddle correctly?
YES NO
Furthermore, the man in the second and third lines are wearing a whistle, but the man in the last line is not wearing a whistle. Presumably the value of the whistle should be accounted for to get the correct answer.
The pictures can be translated into the following equations:
shoes + shoes + shoes = 30
shoes + (man + whistle) + (man + whistle) = 20
(man + whistle) + 2(whistles) + 2(whistles) = 13
shoes + (man) x (whistle) = ?
From the first equation we can solve for the shoes value:
shoes + shoes + shoes = 30
3(shoes) = 30
shoes = 10
We can then solve the second equation for the (man + whistle) value:
shoes + (man + whistle) + (man + whistle) = 20
10 + 2(man + whistle) = 20
2(man + whistle) = 10
man + whistle = 5
Then we solve the third equation for the whistle:
(man + whistle) + 2(whistles) + 2(whistles) = 13
5 + 4(whistles) = 13
4(whistles) = 8
whistle = 2
We also need to solve for the value of the man:
man + whistle = 5
man + 2 = 5
man = 3
Now we can evaluate the final expression, remembering the order of operations that multiplication should be evaluated before addition:
shoes + (man) x (whistle) = ?
10 + 3 x 2
= 10 + 3 x 2
= 10 + 6
= 16 Did you answer this riddle correctly?
YES NO
How Many Children?
Mr. Smith has 4 daughters. Each of his daughters has a brother.
How many children does Mr. Smith have?
How many children does Mr. Smith have?
Hint:
He has 5 children, all of the daughters have the same 1 brother. Did you answer this riddle correctly?
YES NO
YES NO
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