Eating Burgers Riddle
If one and a half boys, eat one and a half burgers in one and a half hours.
How many burgers can 9 boys eat in 3 hours ?
How many burgers can 9 boys eat in 3 hours ?
Hint:
18
More hours => more burgers.
More boys => more burgers.
The time become twice (3 hours / 1.5 hours).
Boys become six times (9 / 1.5).
Number of burgers = 2 * 6 * Original(1.5)
= 18 Did you answer this riddle correctly?
YES NO
More hours => more burgers.
More boys => more burgers.
The time become twice (3 hours / 1.5 hours).
Boys become six times (9 / 1.5).
Number of burgers = 2 * 6 * Original(1.5)
= 18 Did you answer this riddle correctly?
YES NO
10 Boxes Riddle
There are ten boxes containing some balls. Each of the ball weighs exactly 10 grams. One of those boxes have defective balls (all the defective balls weigh 9 grams each).
An electronic weighing machine is provided to you and you are allowed only one chance of weighing on it.
How will you find out which box has defective balls ?
An electronic weighing machine is provided to you and you are allowed only one chance of weighing on it.
How will you find out which box has defective balls ?
Hint:
Let us simplify boxes by naming them from 1 to 10.
Now the trick here is to pick different number of balls from different boxes. So to simplify things, we will pick balls corresponding to box number.
Thus, pick 1 ball from Box 1, 2 balls from box 2, 3 balls from box 3 and so on. You will have 55 balls altogether. Now, put them all in the balance.
If all balls were weighing accurate 10 grams, the total weight of the 55 balls would have been 550 grams. But one of the box must have had the defective balls.
Suppose if the defective balls were in box number 2, then the total weight will be 2 grams less than 550. If the defective balls were in box 8, the total weight will be less than 8 grams from 550. In this way, you will be able to identify which box has the defective balls. Did you answer this riddle correctly?
YES NO
Now the trick here is to pick different number of balls from different boxes. So to simplify things, we will pick balls corresponding to box number.
Thus, pick 1 ball from Box 1, 2 balls from box 2, 3 balls from box 3 and so on. You will have 55 balls altogether. Now, put them all in the balance.
If all balls were weighing accurate 10 grams, the total weight of the 55 balls would have been 550 grams. But one of the box must have had the defective balls.
Suppose if the defective balls were in box number 2, then the total weight will be 2 grams less than 550. If the defective balls were in box 8, the total weight will be less than 8 grams from 550. In this way, you will be able to identify which box has the defective balls. Did you answer this riddle correctly?
YES NO
New York Multiplication Riddle
Hint:
Gym Class Riddle
Four different-colored balls are being used in a gym class activity blue, red, yellow and orange. Each student must hold two different-colored balls, but no two students can have the same two colors (for example, only one student can hold the blue and red ball).
How many students can play the game?
How many students can play the game?
Hint:
Six. Explanation: 1. Blue Red
2. Blue Yellow
3. Blue Orange
4. Red Yellow
5. Red Orange
6. Yellow Orange Did you answer this riddle correctly?
YES NO
2. Blue Yellow
3. Blue Orange
4. Red Yellow
5. Red Orange
6. Yellow Orange Did you answer this riddle correctly?
YES NO
Malcolm's Age Riddle
Malcolm is the number of weeks of his fathers age treated as days and his grandfathers age in months. All three of their ages add up to 120 years. How old is Malcolm, his father and his grandfather?
Hint:
Malcolm is 6.
The father is 42. 42 days = 6 weeks.
The grandfather is 72. 72 months = 6 years. Did you answer this riddle correctly?
YES NO
The father is 42. 42 days = 6 weeks.
The grandfather is 72. 72 months = 6 years. Did you answer this riddle correctly?
YES NO
Seventeen Apples Riddle
Hint:
A Rickety Bridge Riddle
Four people need to cross a rickety bridge at night. Unfortunately, they have only one torch and the bridge is too dangerous to cross without one. The bridge is only strong enough to support two people at a time. Not all people take the same time to cross the bridge. Times for each person: 1 min, 2 mins, 7 mins and 10 mins. What is the shortest time needed for all four of them to cross the bridge?
Hint:
17 mins.
The initial solution most people will think of is to use the fastest person as an usher to guide everyone across. How long would that take? 10 + 1 + 7 + 1 + 2 = 21 mins. Is that it? No. That would make this question too simple even as a warm up question.
Let's brainstorm a little further. To reduce the amount of time, we should find a way for 10 and 7 to go together. If they cross together, then we need one of them to come back to get the others. That would not be ideal. How do we get around that? Maybe we can have 1 waiting on the other side to bring the torch back. Ahaa, we are getting closer. The fastest way to get 1 across and be back is to use 2 to usher 1 across. So let's put all this together.
1 and 2 go cross
2 comes back
7 and 10 go across
1 comes back
1 and 2 go across (done)
Total time = 2 + 2 + 10 + 1 + 2 = 17 mins Did you answer this riddle correctly?
YES NO
The initial solution most people will think of is to use the fastest person as an usher to guide everyone across. How long would that take? 10 + 1 + 7 + 1 + 2 = 21 mins. Is that it? No. That would make this question too simple even as a warm up question.
Let's brainstorm a little further. To reduce the amount of time, we should find a way for 10 and 7 to go together. If they cross together, then we need one of them to come back to get the others. That would not be ideal. How do we get around that? Maybe we can have 1 waiting on the other side to bring the torch back. Ahaa, we are getting closer. The fastest way to get 1 across and be back is to use 2 to usher 1 across. So let's put all this together.
1 and 2 go cross
2 comes back
7 and 10 go across
1 comes back
1 and 2 go across (done)
Total time = 2 + 2 + 10 + 1 + 2 = 17 mins Did you answer this riddle correctly?
YES NO
Cost Of A Ball Riddle
A bat and a ball cost $1.10. The bat costs one dollar more than the ball. How much does the ball cost?
Hint:
The ball costs 5 cents. One dollar more than 5c is $1.05. The sum of which is $1.10. Did you answer this riddle correctly?
YES NO
YES NO
3 Apples Riddle
Hint:
The Greater Dozen Riddle
Hint:
10 Zebras Riddle
Hint:
Zebras And Ostriches In The Zoo
There are zebras and ostriches in this Zoo.
You count 80 heads and 200 legs.
Can you find the number of Zebras and the number of Ostriches in the Zoo?
You count 80 heads and 200 legs.
Can you find the number of Zebras and the number of Ostriches in the Zoo?
Hint:
The number of Ostriches = 60 & The number of Zebras = 20 Did you answer this riddle correctly?
YES NO
YES NO
Cakes For Grandma Riddle
You are on your way to visit your Grandma, who lives at the end of the valley. It's her birthday, and you want to give her the cakes you've made.
Between your house and her house, you have to cross 7 bridges, and as it goes in the land of make believe, there is a troll under every bridge! Each troll, quite rightly, insists that you pay a troll toll. Before you can cross their bridge, you have to give them half of the cakes you are carrying, but as they are kind trolls, they each give you back a single cake.
How many cakes do you have to leave home with to make sure that you arrive at Grandma's with exactly 2 cakes?
Between your house and her house, you have to cross 7 bridges, and as it goes in the land of make believe, there is a troll under every bridge! Each troll, quite rightly, insists that you pay a troll toll. Before you can cross their bridge, you have to give them half of the cakes you are carrying, but as they are kind trolls, they each give you back a single cake.
How many cakes do you have to leave home with to make sure that you arrive at Grandma's with exactly 2 cakes?
Hint:
2: At each bridge you are required to give half of your cakes, and you receive one back. Which leaves you with 2 cakes after every bridge. Did you answer this riddle correctly?
YES NO
YES NO
Little Johnny's Cats Riddle
Little Johnny's teacher asks him, "If I gave you two cats, then two more, and two more cats; how many would you have?"
Little Johnny replies, "Seven!"
His teacher asks him again more slowly, "If I gave you two cats, then two more, and two more cats; how many would you have?"
But again Little Johnny replies, "Seven!"
Next she asks, "If I get two cats, then two more, and two more cats; how many would I have?"
Little Johnny replies, "Six!"
"Good Job Johnny! Now if I gave you two cats, then two more, and two more cats; how many would you have?"
Johnny thinks for a second, "Seven."
But Johnny is not wrong. Why?
Little Johnny replies, "Seven!"
His teacher asks him again more slowly, "If I gave you two cats, then two more, and two more cats; how many would you have?"
But again Little Johnny replies, "Seven!"
Next she asks, "If I get two cats, then two more, and two more cats; how many would I have?"
Little Johnny replies, "Six!"
"Good Job Johnny! Now if I gave you two cats, then two more, and two more cats; how many would you have?"
Johnny thinks for a second, "Seven."
But Johnny is not wrong. Why?
Hint:
Making Ten Riddle
Hint:
Yes it is possible in Roman Numerals. In Roman Numerals,
9 = IX
10 = X
11 = XI
Thus by removing one from 9, you are getting 10 and by removing one from 11, you are getting 10 again. Did you answer this riddle correctly?
YES NO
9 = IX
10 = X
11 = XI
Thus by removing one from 9, you are getting 10 and by removing one from 11, you are getting 10 again. Did you answer this riddle correctly?
YES NO
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