IN A STREET THERE ARE FIVE HOUSES PAINTED FIVE DIFFERENT COLOURS IN EACH HOUSE LIVES A PERSON OF DIFFERENT NATIONALITY THESE FIVE HOME OWNERS EACH DRINK A DIFFERENT KIND OF B RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

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Riddles and Answers © 2024

Person Who Built It Sold It Riddle

Hint:
A coffin
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If The Streets Are Crowded But Nobody Lives Here Riddle

Hint: If it is stated that there are people somewhere but there is no life, those people are dead.
The cemetery
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Keys To A Banana

Hint:
A monkey
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What Color Is The Bear?

Hint:
The bear is white since the house is built on the North Pole.
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Bowling Cats Riddle

Hint:
Alley cats!
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Busy Busy Bee

Hint:
Bumble Bee!
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My House Has No Doors Riddle

Hint:
A baby bird in an egg.
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On Top A Joppa House Riddle

Hint:
Peter
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Beach Grub Riddle

Hint:
A sandwich
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A House With A Post On Top

Hint:
A boat.
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Bar Ninja Riddle

Hint:
Wata!
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The Reckless Bus Driver Riddle

Hint:
He was walking...not driving.
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Soccer Drinks Riddle

Hint:
Penal-Tea
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Losing A New York Bet

Hint:
This problem can be best solved using the pigeonhole principle.

The argument will go like this:
Assume that all the non-bald people in NYC have different number of hairs on their head. The population is about 9 million and let us assume that there are 8 million among them who are not bald.

Now, those 8 million people need to have different number of hairs. On an average, people have just 100, 000 hairs on their head. If we keep on assuming that there is someone with just one hair, someone with two, someone with three and so on, there will be 7, 900, 00 other people left who will have more than 100, 000 hairs on their head and need different number of hairs.

Now, as per this assumption, if we keep increasing one hair for each person, to make everybody hair different in numbers, we will come across someone with 8, 000, 000 hairs. But that is practically impossible (even 1, 000, 000 is impossible). Thus there must be two people who are having same number of hairs.
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A Rickety Bridge Riddle

Hint:
17 mins.

The initial solution most people will think of is to use the fastest person as an usher to guide everyone across. How long would that take? 10 + 1 + 7 + 1 + 2 = 21 mins. Is that it? No. That would make this question too simple even as a warm up question.

Let's brainstorm a little further. To reduce the amount of time, we should find a way for 10 and 7 to go together. If they cross together, then we need one of them to come back to get the others. That would not be ideal. How do we get around that? Maybe we can have 1 waiting on the other side to bring the torch back. Ahaa, we are getting closer. The fastest way to get 1 across and be back is to use 2 to usher 1 across. So let's put all this together.

1 and 2 go cross
2 comes back
7 and 10 go across
1 comes back
1 and 2 go across (done)

Total time = 2 + 2 + 10 + 1 + 2 = 17 mins
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