5 PERSON IN A ROOM AND I SHOOT 4 HOW MANYYL IN A ROOM AND I SHOOT 4 HOW MANYYL RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

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Riddles and Answers © 2024

Pearl Problems Riddle

Hint: If you took out 2 pearls, you would have about a 50% chance of getting 2 gold bars. However, you can take even more pearls and still retain the 50% chance.
Take out 5000 pearls. If the remaining pearl is white, then you've won 5000 gold bars!
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Hint: Their dad is a very smart person.
Believe it or not, both Mike and James have a 1/2 chance of winning.

James wins if:
-he calls both coin flips right = 1/2 x 1/2 = 1/4
OR
-he does not call both coin flips right, Mike does not call the die roll correctly, and he guesses the number on the spinner right = 3/4 x 5/6 x 2/5 = 30/120 = 1/4

1/4 + 1/4 = 1/2

Mike wins if:
-James does not call both coin flips right and he calls the die roll correctly = 3/4 x 1/6 = 3/24 = 1/8
OR
-James does not call both coin flips right, he does not call the die roll correctly, and Mike does not guess the number on the spinner right = 3/4 x 5/6 x 3/5 = 45/120 = 3/8

1/8 + 3/8 = 1/2

Of course, dad could have just flipped a coin
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The Secret Santa Exchange

Hint: It's not as difficult as it seems. It's the number of ways the friends can form a circle divided by the number of ways the names can be drawn out of the hat.
1/10

For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is

(n-1)! / n!

Since n! = (n-1)! * n (for n > 1), this can be rewritten as

(n-1)! / (n*(n-1)!)

Factoring out the (n-1)! from the numerator and denominator leaves

1/n

as the probability.
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The Coin Toss Riddle

Hint: Think what would be most likely to happen if you chose HHH, would this be a good decision?
The answer is to let your friend go first. This puzzle is based on an old game/scam called Penny Ante. No matter what you picked, your friend would be able to come up with a combination which would be more likely to beat yours. For example, if you were to choose HHH, then unless HHH was the first combination to come up you would eventually lose since as soon as a Tails came up, the combination THH would inevitably come up before HHH. The basic formula you can use for working out which combination you should choose is as follows. Simply take his combination (eg. HHT) take the last term in his combination, put it at the front (in this case making THH) and your combination will be more likely to come up first. Try it on your friends!
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Passing 2nd Place

Hint:
You would be in 2nd place. You passed the person in second place, not first.
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Unwilling To Kiss

Hint:
A spider.
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Without A Father Riddle

Hint:
Joshua, because he was the son of nun (none).
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The Most Amount Of Money

Hint:
Mary! John 'had' 200k but is past tense. Mark 'will' have 500k but does not current have it as the question asks who 'has' the most amount of money.
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Cindy Has 5 Kids Riddle

Hint:
The 5th kids name is What. "What is the name of the 5th kid."
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You See A Boat Riddle

Hint:
They are all married
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There Was A Plane Crash Riddle

Hint:
Married couples
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I Am A Protector Riddle

Hint:
Sunglasses
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Alex And The New Neighbor Riddle

Hint:
The new neighbors name is 'Who.' ...When the mom SUPPOSEDLY asked "Who is the new neighbor?", she wasn't asking; she was making a statement. "Who is [the name of] the new neighbor."
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I Was Right In The Middle Of February Riddle

Hint:
The number 15
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Prisoner Hat Riddle

Four inmates are cleaning up a littered beach as part of a prisoner work program. The warden, who happens to be overseeing the work, decides to play a little game with the prisoners. He tells them that if they win the game he will let them go free! He then proceeds to bury each prisoner up to his neck in sand as shown.

There is a wall between prisoners C and D (which cannot be seen through or around). Prisoner A can see prisoners B and C (by moving his head to the side). Prisoner B can see prisoner C. Prisoners C and D see only the wall.

The prisoners are immobilized in the ground and can't twist their body to see the person behind them. The warden shows them two black hats and two white hats and then puts the hats in a bag to conceal them. He then stands behind each prisoner, chooses a hat from the bag, and puts it on their head. The color of each prisoner's hat is shown in the image above.

The rules are simple. If any prisoner can figure out the color of the hat on his head, all four prisoners will be set free. But they must be sure, if one of them simply guesses and is wrong, they will all be shot dead! The prisoners are not allowed to talk to each other and they have 10 seconds.

The warden counts down "ten, nine, eight, seven". All four prisoners are silent. The warden smiles, knowing that he put the hats on in such a way that no prisoner could possibly know the color of the hat they had on. He continues "six, five, four, thr.."

"I know the color of my hat!" one of the prisoners finally blurts out.

Which prisoner called out and why is he 100% certain of the color of his hat?
Four inmates are cleaning up a littered beach as part of a prisoner work program. The warden, who happens to be overseeing the work, decides to play a little game with the prisoners. He tells them that if they win the game he will let them go free! He then proceeds to bury each prisoner up to his neck in sand as shown.

There is a wall between prisoners C and D (which cannot be seen through or around). Prisoner A can see prisoners B and C (by moving his head to the side). Prisoner B can see prisoner C. Prisoners C and D see only the wall.

The prisoners are immobilized in the ground and can't twist their body to see the person behind them. The warden shows them two black hats and two white hats and then puts the hats in a bag to conceal them. He then stands behind each prisoner, chooses a hat from the bag, and puts it on their head. The color of each prisoner's hat is shown in the image above.

The rules are simple. If any prisoner can figure out the color of the hat on his head, all four prisoners will be set free. But they must be sure, if one of them simply guesses and is wrong, they will all be shot dead! The prisoners are not allowed to talk to each other and they have 10 seconds.

The warden counts down "ten, nine, eight, seven". All four prisoners are silent. The warden smiles, knowing that he put the hats on in such a way that no prisoner could possibly know the color of the hat they had on. He continues "six, five, four, thr.."

"I know the color of my hat!" one of the prisoners finally blurts out.

Which prisoner called out and why is he 100% certain of the color of his hat?
Hint:
Prisoner B.

If prisoners B and C had the same color hat on, prisoner A would have know immediately that his hat was the other color (there are only two hats of each color). Since prisoner A was silent, prisoners B and C must have different colored hats. Prisoner B realized this and knew that his hat was not the same color as prisoner C, therefore his hat must be black!
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