The Game Of Cards Riddle
In a game of cards, GEORGE partnered with MARY, while TED had to choose a partner. He could have chosen ANN, EDNA, JOAN or ANGELA. Whom did he choose and why?
Hint:
ANN. If you give each letter a number according to its position in the alphabet:
TED = 20 + 5 + 4 = 29
ANN = 1 + 14 + 14 = 29
(George and Mary each add to 57) Did you answer this riddle correctly?
YES NO
TED = 20 + 5 + 4 = 29
ANN = 1 + 14 + 14 = 29
(George and Mary each add to 57) Did you answer this riddle correctly?
YES NO
Man's Best Friend Riddle
The earth is black and white to me
Other colors I can not see
Some call me man's best friend
Because I'll stick by your side til the very end
Other colors I can not see
Some call me man's best friend
Because I'll stick by your side til the very end
Hint:
Old Chinese Man Riddle
Hint:
A Man Looks At A Painting In A Museum Riddlle
Hint:
Carbon And Hydrogen Riddle
Hint:
Carrying Children Riddle
Hint:
Black On Black Riddle
How did the driver see the man?
Hint:
The Smartest Man Riddle
Hint:
Carried In A Box Riddle
Before you get engaged
In a small box it is carried
It is what gets exchanged
On the day that you get married
In a small box it is carried
It is what gets exchanged
On the day that you get married
Hint:
Man In The Grave Riddle
The second man says, "Who is in that grave?"
The first man points to the grave and says, "Brothers and Sisters I have none, But that man's father, is my father's son."
*Who is in the grave?*
Hint:
"That mans father is my fathers son" refers to the speaker. *Since he's pointing to the grave, it means he's in the grave.* Did you answer this riddle correctly?
YES NO
YES NO
Carving A Face Riddle
Hint:
Carrying Fish Riddle
Hint:
Carton Of Eggs Riddle
Hint:
5 eggs are taken by the first 5 people, then the 6th person takes the egg , while its still in the carton!! Did you answer this riddle correctly?
YES NO
YES NO
Rhymes With Carriage Riddle
Hint:
100 Blank Cards Riddle
Someone offers you the following deal:
There is a deck of 100 initially blank cards. The dealer is allowed to write ANY positive integer, one per card, leaving none blank. You are then asked to turn over as many cards as you wish. If the last card you turn over is the highest in the deck, you win; otherwise, you lose.
Winning grants you $50, and losing costs you only the $10 you paid to play.
Would you accept this challenge?
There is a deck of 100 initially blank cards. The dealer is allowed to write ANY positive integer, one per card, leaving none blank. You are then asked to turn over as many cards as you wish. If the last card you turn over is the highest in the deck, you win; otherwise, you lose.
Winning grants you $50, and losing costs you only the $10 you paid to play.
Would you accept this challenge?
Hint: Perhaps thinking in terms of one deck is the wrong approach.
Yes!
A sample strategy:
Divide the deck in half and turn over all lower 50 cards, setting aside the highest number you find. Then turn over the other 50 cards, one by one, until you reach a number that is higher than the card you set aside: this is your chosen "high card."
Now, there is a 50% chance that the highest card is contained in the top 50 cards (it is or it isn't), and a 50% chance that the second-highest card is contained in the lower 50. Combining the probabilities, you have a 25% chance of constructing the above situation (in which you win every time).
This means that you'll lose three out of four games, but for every four games played, you pay $40 while you win one game and $50. Your net profit every four games is $10.
Obviously, you have to have at least $40 to start in order to apply this strategy effectively. Did you answer this riddle correctly?
YES NO
A sample strategy:
Divide the deck in half and turn over all lower 50 cards, setting aside the highest number you find. Then turn over the other 50 cards, one by one, until you reach a number that is higher than the card you set aside: this is your chosen "high card."
Now, there is a 50% chance that the highest card is contained in the top 50 cards (it is or it isn't), and a 50% chance that the second-highest card is contained in the lower 50. Combining the probabilities, you have a 25% chance of constructing the above situation (in which you win every time).
This means that you'll lose three out of four games, but for every four games played, you pay $40 while you win one game and $50. Your net profit every four games is $10.
Obviously, you have to have at least $40 to start in order to apply this strategy effectively. Did you answer this riddle correctly?
YES NO
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