Throw Me Riddle
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3 Cheerleaders 12 Hot Fudge Sundaes
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Jason Voorhees And A Box Of Cherrios Riddle
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Clean But Not Water Riddle
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Ghouls And Owls Riddle
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A Grandfather Clock Riddle
A grandfather clock chimes the appropriate number of times to indicate the hour, as well as chiming once at each quarter hour. If you were in another room and heard the clock chime just once, what would be the longest period of time you would have to wait in order to be certain of the correct time? Assuming you had absolutely no clue what time it was.
Hint:
You would have to wait 90 minutes between 12:15 and 1:45. Once you had heard seven single chimes, you would know that the next chime would be two chimes for 2 oclock.
In order for daylight savings time to come into play, you would have to manually set the clock back, which unless you did it with your eyes closed would indicate the time to you. Did you answer this riddle correctly?
YES NO
In order for daylight savings time to come into play, you would have to manually set the clock back, which unless you did it with your eyes closed would indicate the time to you. Did you answer this riddle correctly?
YES NO
A Snowman With A Witch
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The Restaurants In Australia Riddle
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An Apple And A Christmas Tree Riddle
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Karate Expert With A Pig Riddle
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What Do Cows Drink Riddle
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Chicken Fox And Grain Riddle
You have a fox, a chicken and a sack of grain. You must cross a river with only one of them at a time. If you leave the fox with the chicken he will eat it; if you leave the chicken with the grain he will eat it. How can you get all three across safely?
Hint:
Take the chicken over first. Go back and bring the grain next, but instead of leaving the chicken with the grain, come back with the chicken. Leave the chicken on the first side and take the fox with you. Leave it on the other side with the grain. Finally, go back over and get the chicken and bring it over. Did you answer this riddle correctly?
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YES NO
12 Islanders Teeter Totter Riddle
There is an island with 12 islanders. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11.
You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. There are no scales or other weighing device on the island.
How can you find out which islander is the one that has a different weight?
You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. There are no scales or other weighing device on the island.
How can you find out which islander is the one that has a different weight?
Hint:
Six on one side - six on the other = one side is heavier.
Take the heavier six men, divide them into three and three (random).
Three on one side - three on the other = one side will one heavier.
Divide that three men from the heavier side side, have one on one side - one on the other.
Two results can determine which of the last three men weight is a different weight than each other.
With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.
Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.
You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."
Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
YES NO
Take the heavier six men, divide them into three and three (random).
Three on one side - three on the other = one side will one heavier.
Divide that three men from the heavier side side, have one on one side - one on the other.
Two results can determine which of the last three men weight is a different weight than each other.
With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.
Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.
You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."
Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
YES NO
20 Plus 20 Plus 20 Riddle
Hint:
Fox Goose Beans Riddle
Once upon a time a farmer went to a market and purchased a fox, a goose, and a bag of beans. On his way home, the farmer came to the bank of a river and rented a boat. But in crossing the river by boat, the farmer could carry only himself and a single one of his purchases: the fox, the goose, or the bag of beans. If left unattended together, the fox would eat the goose, or the goose would eat the beans. The farmer's challenge was to carry himself and his purchases to the far bank of the river, leaving each purchase intact. How did he do it?
Hint:
The first step must be to take the goose across the river, as any other will result in the goose or the beans being eaten. When the farmer returns to the original side, he has the choice of taking either the fox or the beans across next. If he takes the fox across, he would have to return to get the beans, resulting in the fox eating the goose. If he takes the beans across second, he will need to return to get the fox, resulting in the beans being eaten by the goose. The dilemma is solved by taking the fox (or the beans) over and bringing the goose back. Now he can take the beans (or the fox) over, and finally return to fetch the goose. His actions in the solution are summarized in the following steps: Take the Goose over Return Take the beans over Return with the goose Take the fox over Return Take goose over Thus there are seven crossings, four forward and three back. Did you answer this riddle correctly?
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YES NO
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