Presidential Promises Riddle
Ronald has a rare opportunity to meet the President of the United States. During his visit the president gives him a gift but tells Ronald he is never to sell it unless he sees the president again. Ronald consents, but the president dies later that year. Years later a man offers to buy the Presidents gift for $1000. Ronald agrees and exchanges the gift for 20 crisp $50 bills. Did he keep his promise?
Hint:
Yes. The president was Ulysses S. Grant, who died in 1885 and whose face has been on the $50 bill since 1913. He saw the president on the bills before he made the exchange. Did you answer this riddle correctly?
YES NO
YES NO
A List Of Names Riddle
Lennie was cleaning up some old papers in his office and found a list with the following names:
Washington
Jefferson
Lincoln
Hamilton
Jackson
Grant
The last name on the list was mostly worn away and he couldnt make it out. What was the last name and why?
Washington
Jefferson
Lincoln
Hamilton
Jackson
Grant
The last name on the list was mostly worn away and he couldnt make it out. What was the last name and why?
Hint:
Franklin. Its a list of the men on U.S. currency, $1, $2, $5, $10, $20 and $50. The $100 bill has Franklin. And an interesting tidbit is that Hamilton, along with Franklin, are the only two men in the list who did not serve as president. Did you answer this riddle correctly?
YES NO
YES NO
Adding Eights Riddle
Hint:
Bigger Upside Down Riddle
Hint:
Always Right Riddle
Hint:
A Dime And A Dollar Riddle
You have a dime and a dollar, you buy a dog and a collar, the dog is a dollar more than the collar, how much is the collar?
Hint:
Coins In My Wallet Riddle
I have 100 coins in my wallet.
What is the minimum number of coin(s), I would be required in order to make sure each coin touched exactly three other coins.
What is the minimum number of coin(s), I would be required in order to make sure each coin touched exactly three other coins.
Hint:
4
3 placed flat on the table in a triangle(touching each other) and put the fourth one on top of them in the middle. Did you answer this riddle correctly?
YES NO
3 placed flat on the table in a triangle(touching each other) and put the fourth one on top of them in the middle. Did you answer this riddle correctly?
YES NO
Eating Burgers Riddle
If one and a half boys, eat one and a half burgers in one and a half hours.
How many burgers can 9 boys eat in 3 hours ?
How many burgers can 9 boys eat in 3 hours ?
Hint:
18
More hours => more burgers.
More boys => more burgers.
The time become twice (3 hours / 1.5 hours).
Boys become six times (9 / 1.5).
Number of burgers = 2 * 6 * Original(1.5)
= 18 Did you answer this riddle correctly?
YES NO
More hours => more burgers.
More boys => more burgers.
The time become twice (3 hours / 1.5 hours).
Boys become six times (9 / 1.5).
Number of burgers = 2 * 6 * Original(1.5)
= 18 Did you answer this riddle correctly?
YES NO
10 Boxes Riddle
There are ten boxes containing some balls. Each of the ball weighs exactly 10 grams. One of those boxes have defective balls (all the defective balls weigh 9 grams each).
An electronic weighing machine is provided to you and you are allowed only one chance of weighing on it.
How will you find out which box has defective balls ?
An electronic weighing machine is provided to you and you are allowed only one chance of weighing on it.
How will you find out which box has defective balls ?
Hint:
Let us simplify boxes by naming them from 1 to 10.
Now the trick here is to pick different number of balls from different boxes. So to simplify things, we will pick balls corresponding to box number.
Thus, pick 1 ball from Box 1, 2 balls from box 2, 3 balls from box 3 and so on. You will have 55 balls altogether. Now, put them all in the balance.
If all balls were weighing accurate 10 grams, the total weight of the 55 balls would have been 550 grams. But one of the box must have had the defective balls.
Suppose if the defective balls were in box number 2, then the total weight will be 2 grams less than 550. If the defective balls were in box 8, the total weight will be less than 8 grams from 550. In this way, you will be able to identify which box has the defective balls. Did you answer this riddle correctly?
YES NO
Now the trick here is to pick different number of balls from different boxes. So to simplify things, we will pick balls corresponding to box number.
Thus, pick 1 ball from Box 1, 2 balls from box 2, 3 balls from box 3 and so on. You will have 55 balls altogether. Now, put them all in the balance.
If all balls were weighing accurate 10 grams, the total weight of the 55 balls would have been 550 grams. But one of the box must have had the defective balls.
Suppose if the defective balls were in box number 2, then the total weight will be 2 grams less than 550. If the defective balls were in box 8, the total weight will be less than 8 grams from 550. In this way, you will be able to identify which box has the defective balls. Did you answer this riddle correctly?
YES NO
New York Multiplication Riddle
Hint:
Gym Class Riddle
Four different-colored balls are being used in a gym class activity blue, red, yellow and orange. Each student must hold two different-colored balls, but no two students can have the same two colors (for example, only one student can hold the blue and red ball).
How many students can play the game?
How many students can play the game?
Hint:
Six. Explanation: 1. Blue Red
2. Blue Yellow
3. Blue Orange
4. Red Yellow
5. Red Orange
6. Yellow Orange Did you answer this riddle correctly?
YES NO
2. Blue Yellow
3. Blue Orange
4. Red Yellow
5. Red Orange
6. Yellow Orange Did you answer this riddle correctly?
YES NO
Malcolm's Age Riddle
Malcolm is the number of weeks of his fathers age treated as days and his grandfathers age in months. All three of their ages add up to 120 years. How old is Malcolm, his father and his grandfather?
Hint:
Malcolm is 6.
The father is 42. 42 days = 6 weeks.
The grandfather is 72. 72 months = 6 years. Did you answer this riddle correctly?
YES NO
The father is 42. 42 days = 6 weeks.
The grandfather is 72. 72 months = 6 years. Did you answer this riddle correctly?
YES NO
Seventeen Apples Riddle
Hint:
A Rickety Bridge Riddle
Four people need to cross a rickety bridge at night. Unfortunately, they have only one torch and the bridge is too dangerous to cross without one. The bridge is only strong enough to support two people at a time. Not all people take the same time to cross the bridge. Times for each person: 1 min, 2 mins, 7 mins and 10 mins. What is the shortest time needed for all four of them to cross the bridge?
Hint:
17 mins.
The initial solution most people will think of is to use the fastest person as an usher to guide everyone across. How long would that take? 10 + 1 + 7 + 1 + 2 = 21 mins. Is that it? No. That would make this question too simple even as a warm up question.
Let's brainstorm a little further. To reduce the amount of time, we should find a way for 10 and 7 to go together. If they cross together, then we need one of them to come back to get the others. That would not be ideal. How do we get around that? Maybe we can have 1 waiting on the other side to bring the torch back. Ahaa, we are getting closer. The fastest way to get 1 across and be back is to use 2 to usher 1 across. So let's put all this together.
1 and 2 go cross
2 comes back
7 and 10 go across
1 comes back
1 and 2 go across (done)
Total time = 2 + 2 + 10 + 1 + 2 = 17 mins Did you answer this riddle correctly?
YES NO
The initial solution most people will think of is to use the fastest person as an usher to guide everyone across. How long would that take? 10 + 1 + 7 + 1 + 2 = 21 mins. Is that it? No. That would make this question too simple even as a warm up question.
Let's brainstorm a little further. To reduce the amount of time, we should find a way for 10 and 7 to go together. If they cross together, then we need one of them to come back to get the others. That would not be ideal. How do we get around that? Maybe we can have 1 waiting on the other side to bring the torch back. Ahaa, we are getting closer. The fastest way to get 1 across and be back is to use 2 to usher 1 across. So let's put all this together.
1 and 2 go cross
2 comes back
7 and 10 go across
1 comes back
1 and 2 go across (done)
Total time = 2 + 2 + 10 + 1 + 2 = 17 mins Did you answer this riddle correctly?
YES NO
45 Cent Concert Riddle
Mary and Jeffrey were going to a concert. The show featured Jeffrey's favorite band, and Mary's favorite rapper. Together the show was only worth 45 cents. Who performed at the concert?
Hint:
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