MATH MONEY RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

Ne, the bus driver.

On the 1st stop, 5 people get on. On the 2nd stop, 5 people get off and 10 (twice as many as at 1st stop) people get on. On the 3rd stop, 10 people get off. So there are (5 5 + 10 10) 0 passengers left, which leaves the bus driver as the only person on board the bus. Did you answer this riddle correctly?
YES  NO  

Did you answer this riddle correctly?
YES  NO  

Credit or debt. Debt is a problem in many peoples lives, but in order to go to school or make a large purchase, it can be useful. As your debt grows older, its more unpleasant than useful. Did you answer this riddle correctly?
YES  NO  

At a blood bank. Did you answer this riddle correctly?
YES  NO  

Noah Did you answer this riddle correctly?
YES  NO  

Our money! Did you answer this riddle correctly?
YES  NO  

Yes. The president was Ulysses S. Grant, who died in 1885 and whose face has been on the $50 bill since 1913. He saw the president on the bills before he made the exchange. Did you answer this riddle correctly?
YES  NO  

Franklin. Its a list of the men on U.S. currency, $1, $2, $5, $10, $20 and $50. The $100 bill has Franklin. And an interesting tidbit is that Hamilton, along with Franklin, are the only two men in the list who did not serve as president. Did you answer this riddle correctly?
YES  NO  

888 + 88 + 8 + 8 + 8 = 1000. Did you answer this riddle correctly?
YES  NO  

A 6! Did you answer this riddle correctly?
YES  NO  

A right angle Did you answer this riddle correctly?
YES  NO  

A nickel. The dog cost $ 1.05. Did you answer this riddle correctly?
YES  NO  

4

3 placed flat on the table in a triangle(touching each other) and put the fourth one on top of them in the middle. Did you answer this riddle correctly?
YES  NO  

18

More hours => more burgers.
More boys => more burgers.

The time become twice (3 hours / 1.5 hours).
Boys become six times (9 / 1.5).

Number of burgers = 2 * 6 * Original(1.5)
= 18 Did you answer this riddle correctly?
YES  NO  

Let us simplify boxes by naming them from 1 to 10.
Now the trick here is to pick different number of balls from different boxes. So to simplify things, we will pick balls corresponding to box number.

Thus, pick 1 ball from Box 1, 2 balls from box 2, 3 balls from box 3 and so on. You will have 55 balls altogether. Now, put them all in the balance.

If all balls were weighing accurate 10 grams, the total weight of the 55 balls would have been 550 grams. But one of the box must have had the defective balls.

Suppose if the defective balls were in box number 2, then the total weight will be 2 grams less than 550. If the defective balls were in box 8, the total weight will be less than 8 grams from 550. In this way, you will be able to identify which box has the defective balls. Did you answer this riddle correctly?
YES  NO