In The Jar Riddle
A jar is put on the edge of the table in such a way that half of it is left hanging. What is in the jar?
Hint:
Filled With T Riddle
Hint:
A Girl Unlocks Her Boyfriend's Phone Riddle
A girl unlocks her boyfriend's phone. She found three different contacts having the same name "LOVE". 1st "Love" is the daughter of his dad's dad daughter in law. 2nd "Love" is the mother of his mother and 3rd one is she herself.
Hows the 1st contact is related to the 2nd one?
Hows the 1st contact is related to the 2nd one?
Hint:
I Have 6 Eggs
Hint: The eggs aren't specified.
Penny Has 5 Daughters Riddle
Penny has 5 children.
The 1st is named January.
2nd kid is February.
Her 3rd is called March.
4th is April.
What is the name of the 5th.
The 1st is named January.
2nd kid is February.
Her 3rd is called March.
4th is April.
What is the name of the 5th.
Hint:
If your answer was "Penny", you were wrong.!!
If your answer was "May", you were wrong again!!
Let us tell you the fact that there is no question asked here. This is just for your information that name of the 5th children is "What". If you are still not sure, just read the riddle again. "What is the name of the 5th." Riddle itself says that name of the 5th children is What and there is no question mark at the end. Did you answer this riddle correctly?
YES NO
If your answer was "May", you were wrong again!!
Let us tell you the fact that there is no question asked here. This is just for your information that name of the 5th children is "What". If you are still not sure, just read the riddle again. "What is the name of the 5th." Riddle itself says that name of the 5th children is What and there is no question mark at the end. Did you answer this riddle correctly?
YES NO
What Do Cows Drink Riddle
Hint:
Borrow $50 From Mom And $50 From Dad Riddle
I borrowed $50 from mom and $50 from dad to buy a bag costing $97. After the purchase, I had $3 left. I returned $1 to dad and $1 to mom, and reserved $1 for myself. I now owe $49+$49=$98 plus the $1 I reserved for myself, which is $99. Where is the missing $1?
Hint:
Total Money taken = $100($50+$50)
Now,
Bag's Price = $ 97
Remaining Amount = $100 - $97
= $ 3
Returned = $ 1 + $ 1
=$2
In pocket = $1
Total money owed = $100- ( Returned amount)
= $98( Bag's amount and reserved amount)
So, it was a calculation mistake. Did you answer this riddle correctly?
YES NO
Now,
Bag's Price = $ 97
Remaining Amount = $100 - $97
= $ 3
Returned = $ 1 + $ 1
=$2
In pocket = $1
Total money owed = $100- ( Returned amount)
= $98( Bag's amount and reserved amount)
So, it was a calculation mistake. Did you answer this riddle correctly?
YES NO
What Do TSA Agents And NBA Referees Have In Common?
Hint:
Chicken Fox And Grain Riddle
You have a fox, a chicken and a sack of grain. You must cross a river with only one of them at a time. If you leave the fox with the chicken he will eat it; if you leave the chicken with the grain he will eat it. How can you get all three across safely?
Hint:
Take the chicken over first. Go back and bring the grain next, but instead of leaving the chicken with the grain, come back with the chicken. Leave the chicken on the first side and take the fox with you. Leave it on the other side with the grain. Finally, go back over and get the chicken and bring it over. Did you answer this riddle correctly?
YES NO
YES NO
12 Islanders Teeter Totter Riddle
There is an island with 12 islanders. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11.
You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. There are no scales or other weighing device on the island.
How can you find out which islander is the one that has a different weight?
You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. There are no scales or other weighing device on the island.
How can you find out which islander is the one that has a different weight?
Hint:
Six on one side - six on the other = one side is heavier.
Take the heavier six men, divide them into three and three (random).
Three on one side - three on the other = one side will one heavier.
Divide that three men from the heavier side side, have one on one side - one on the other.
Two results can determine which of the last three men weight is a different weight than each other.
With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.
Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.
You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."
Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
YES NO
Take the heavier six men, divide them into three and three (random).
Three on one side - three on the other = one side will one heavier.
Divide that three men from the heavier side side, have one on one side - one on the other.
Two results can determine which of the last three men weight is a different weight than each other.
With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.
Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.
You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."
Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
YES NO
April May June Riddle
Billy's mom had 4 children. The 1st one was April, the 2nd was May, and the 3rd was June. What was the 4th child named?
Hint:
20 Plus 20 Plus 20 Riddle
Hint:
Serial Killer Pill Riddle
Here is a serial killer, who kidnaps people and asks them to take 1 of 2 pills. One pill is harmless, and the other one is poisonous. The mystery is: Whichever pill a victim takes, the serial killer takes the other one. But every time the killer survives and the victim is dead.
How is this possible? Why the killer always gets the harmless pill?
How is this possible? Why the killer always gets the harmless pill?
Hint:
The poison was in the glass of water the victim drank. Therefore every time he would survive. Did you answer this riddle correctly?
YES NO
YES NO
26 Sheep In A Field In A Field Riddle
Hint:
12 Pills Riddle
You have 12 pills and they all got the same weight, except for one, which hasn't got the same weight. You don't know if it is heavier or easier. You have one scale to weight the pills. You now have to find out, which pill is the right one (the one with a different weight), but you can use the scale only three times. How do you know, which one is the right one?You have 12 pills and they all got the same weight, except for one, which hasn't got the same weight. You don't know if it is heavier or easier. You have one scale to weight the pills. You now have to find out, which pill is the right one (the one with a different weight), but you can use the scale only three times. How do you know, which one is the right one?
Hint:
E = easier in "1", H = heavier in "1". 1: Weight 4:4. If they balance go to "2", if they don't balance, go to "3". 2: Balance 1:1 of the pills you didn't weight yet. Then weight one you didn't weight and one you did weight. If they balanced in the first weighing, and balanced in the second weighing, the last pill is the right one. If they balanced in the first weighing and didn't balance in the second, the one you didn't use before is the right pill. If they didn't balance at all, it's the pill you weighed twice. If they didn't balance in the first weighing, but balanced in the second, it is the first pill. 3: Weight EHH : EHH. If they balance, weight one you already weighed, with an unweighed and go to "4". If they don't balance go to "5". 4: If they balance, the one you didn't weight at all is the right pill. If they don't balance, the one you only weighed once is the right one. 5: Give away every pill that was once easier AND once heavier. You should only have EHH left. Weight H:H. If they balance, E is the right one. If the don't balance, the one which was only heavier the whole time, is the right pill. Did you answer this riddle correctly?
YES NO
YES NO
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